When you say b= a mod 3^100 +1, do you mean that after you divide a by 3^100, you take the remainder, add 1 to it and get b?
Date: 04 Dec 2011 12:13
Number of posts: 6
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oh. and in that same question "g= 0 mod 3^100 +1" means "g mod(3^100 +1) = 0"? because otherwise g=o always and that seems strange…
Just wanted to say that before this post that was very unclear (to me)…
I thought it meant g(x0)=(0mod(3*100+1)) <=> g(x0)=0 for some unknown x0.
Maybe it might be better to point that out stuff like that in future HW assignments?